A bullet of mass 20 g moving with a velocity of 200 m s –1 gets embedded in a wooden block of mass 980 g.
Calculate the velocity acquired by the block
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Answered by
2
the mass of bullet is 20gm
its velocity is 200m/s(given)
the velocity of the block is,
V=m/Mu
=20/980×200
=
its velocity is 200m/s(given)
the velocity of the block is,
V=m/Mu
=20/980×200
=
Answered by
6
mass of bullet= 20g 20/1000= 0.02kg
velocity of gun= 200m/s
p= m*v
0.02*200= 2kgm/s
mass of wodden block =980g =980/1000= 0.98kg
velocity of wodden= v
A/q law of conservation of momentum
momentum of bullet= momentum of wood
2kgm/s= 0.98*v
2= 98v/100
v=100/49= 2.04m/s.
velocity of gun= 200m/s
p= m*v
0.02*200= 2kgm/s
mass of wodden block =980g =980/1000= 0.98kg
velocity of wodden= v
A/q law of conservation of momentum
momentum of bullet= momentum of wood
2kgm/s= 0.98*v
2= 98v/100
v=100/49= 2.04m/s.
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