A bullet of mass 20 g moving with a velocity of 300 m/s gets embedded in a freely suspended wooden block of mass 880 g. what is the velocity acquired by the block?
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Answer:
11/125 m/s
Explanation:
Here, we have to use conservation of linear momentum
let m be mass of bullet, v be velocity of bullet, M be mass of block, V be velocity of block
therefore,
mv = MV
20 * 300 = 880 * V
therefore, V = 11/125 m/s
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