a bullet of mass 20 g moving with speed 200 m/s strikes on a piece of wood and comes to rest in 0.02 s. what is the resistance offered by the wood
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Answered by
9
m = 20 grams
initial velocity = u = 200 m/s
t = 0.02 sec.
let the acceleration or deceleration = a m/sec^2
v = final velocity = u + a t
0 = 200 + a * 0.02
a = - 10, 000 m/sec^2
the resistance offered = force against the movement of the bullet
= F = m a = 20/1000 kg * 10,000 m/sec^2 = 200 Newtons.
initial velocity = u = 200 m/s
t = 0.02 sec.
let the acceleration or deceleration = a m/sec^2
v = final velocity = u + a t
0 = 200 + a * 0.02
a = - 10, 000 m/sec^2
the resistance offered = force against the movement of the bullet
= F = m a = 20/1000 kg * 10,000 m/sec^2 = 200 Newtons.
Answered by
2
Since v=u+at
0=200+(a)0.02
a=-200÷0.02
=-10000
RESISTANCE =-(ACCELERATION)×MASS
=-(-10000)×20×10^-3
=(10000×20)÷1000
=200 N
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