Question

A bullet of mass 20 gm is horizontally fired with a velocity 150 m/sec from a pistol of mass

2 kg. What is the recoil velocity of the pistol?​

Answer 1

0.15

Step-by-step explanation:

According to law of conservation of linear momentum,

MV = mv.

M is mass of pistol = 2 kg.

m is mass of bullet = 2 g = 2 (10 ^-3) kg.

v = velocity of bullet = 150 m/s.

V is recoil velocity of pistol . V= (m/M) v = [ 2(10^-3)/(2)] (150) = 0.15 m/s

Answer 2

Answer:

A bullet of mass 20g is horizontally fired with a velocity of 150m/s from a pistol with a mass of 2kg. What is the recoil velocity of the pistol?

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According to law of conservation of linear momentum,

MV = mv.

M is mass of pistol = 2 kg.

m is mass of bullet = 2 g = 2 (10 ^-3) kg.

v = velocity of bullet = 150 m/s.

V is recoil velocity of pistol . V= (m/M) v = [ 2(10^-3)/(2)] (150) = 0.15 m/s

Step-by-step explanation:

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