Question

A bullet of mass 20 gm moving with a velocity of 100 m/s strikes a wooden block of mass 800 gm and gets
embedded into it. Calculate velocity of the combined system.​

Answer 1

Answer:

1. Mass of bullet is 20 gm
2. Velocity of bullet is 100m/s
3. Mass of wooden block with the embedded bullet = 800 gm + 20 gm = 820 gm
4. Let velocity of the block embet with bullet be v2

Explanation:

According to law of conservation of momentum

p of bullet = p of embedded block

m× v =. m× v

20×100/1000 = 820 × V2 /1000

2 = 820 × V2 / 1000

2×1000 = 820 × V2

2000/820 = V2

0.41 m/ s