Question

A bullet of mass 20 gram is fired horizontally with a velocity of 150 m s -1 From a pistol of mass 2kg what is a recoil velocity of pistol??

Answer 1

$\huge\pink{Question}$

A bullet of mass 20 gram is fired horizontally with a velocity of 150 {ms} {-1}150ms−1 From a pistol of mass 2kg what is a recoil velocity of pistol?

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$\huge\underline\bold\purple{AnswEr} </p><p>$

$\huge\underline\bold\blue{given} </p><p>$

Mass of the bullet, m = 20 g = 0.02 kg

Velocity of bullet, v $= 150 {ms} {-1}$

Mass of the gun ,M = 2 kg

$\huge\underline\bold\red{to \ find}$

Velocity of gun , V = ?

$\huge\underline\bold\orange{solution} </p><p>$

Before firing, both the gun and bullet are at rest. Therefore, initial momentum (bullet+gun)=0 after firing, final momentum (bullet+gun)= mv + MV

Using the law of conservation of linear momentum,

$mv+MV=0$

$⟹0.02×150+2×V=0$

$⟹3.0+2V=0$

$⟹2V=−3$

$⟹V= −3/2=−1.5ms ^−1$

$⟹V=−1.5ms^ −1$

=>the negative sign shows that the direction of motion of the gun is opposite to the direction of motion of the bullet.

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HOPE IT HELPS!!