A bullet of mass 20 gram is horizontally fired with a velocity of 15 m/s from a pistol of mass 2kg. What is the recoil velocity of the pistol?
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Answer:
Thus, the recoil velocity of the pistol is 1.5 m/s.
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Answer:
Explanation:
Given,
u1 (initial velocity) = 0 m/s
v1 (final velocity) = 15m/s
m1(mass) =20 g = 0.02kg
u2 (initial velocity) = 0 m/s
v2 (final velocity) = v
m2 (mass) = 2kg
By law f conversation of momentum:
total momentum before and after collision remains same
i.e
m1u1 + m2u2 = m1v1 + m2v2
=> 0.02x0 + 2 x 0 = 0.02 x 15 + 2v
=> 2v + 0.3 = 0
v= -0.3/2
v = -0.15
the velocity is negative because recoil is in the opposite direction
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