Question

A bullet of mass 20 gram is horizontally fired with a velocity of 15 m/s from a pistol of mass 2kg. What is the recoil velocity of the pistol?

Answer 1

Answer:

Thus, the recoil velocity of the pistol is 1.5 m/s.

Answer 2

Answer:

Explanation:

Given,

u1 (initial velocity) = 0 m/s

v1 (final velocity) = 15m/s

m1(mass) =20 g = 0.02kg

u2 (initial velocity) = 0 m/s

v2 (final velocity) = v

m2 (mass) =  2kg

By law f conversation of momentum:

total momentum before and after collision remains same

i.e

m1u1 + m2u2 = m1v1 + m2v2

=> 0.02x0 + 2 x 0 = 0.02 x 15 + 2v

=> 2v + 0.3 = 0

v= -0.3/2

v = -0.15

the velocity is negative because recoil is in the opposite direction

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