a bullet of mass 20 gram is horizontally fires with a velocity of150 metre per second from a pistol of mass 2 kg. find the value of recall velocity of pistol
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Use conservation of momentum
M1v1 =-m2v2
0.2x 150 = - 2 v2
0.1 x 150 = - v2
V2 = - 15 m/s
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Answer:
Explanation:
Mass of bullet = 20g=20×10^-3kg. Velocity of bullet= 150m/s
Mass of pistol = 2kg
Velocity of pistol = ?
From the conservation of momentum=
Mass of pistol ×velocity of pistol= mass of bullet ×velocity of bullet
Therefore velocity of pistol = mass of bullet × velocity of bullet÷ mass of pistol.
20×10^-3×150÷2=1.5m/s
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