a bullet of mass 20 kg is fired from a rifle of 5000 kg with velocity of 9.5m/s. what is recoil velocity of the rifle.
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Answer:
Given :-
Given :-mass of bullet = 20 kg .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0190 = 5000 v
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0190 = 5000 vv = \frac{190}{5000}v=5000190
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0190 = 5000 vv = \frac{190}{5000}v=5000190v = 0.038 \: \: \frac{m}{s} .v=0.038sm.
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0190 = 5000 vv = \frac{190}{5000}v=5000190v = 0.038 \: \: \frac{m}{s} .v=0.038sm.therefore ,
Given :-mass of bullet = 20 kg .mass of rifle = 5000 kg .velocity ( u ) = 9.5 m/s .______________________________to find :-the recoil velocity ( v ) of the rifle .______________________________Here , Momentum is Conserved .¤ momentum before firing = 0 .¤ momentum after firing = ( 20 × 9.5 ) - 5000 v .By law of conservation of momentum ,20 × 9.5 - 5000 v = 0190 = 5000 vv = \frac{190}{5000}v=5000190v = 0.038 \: \: \frac{m}{s} .v=0.038sm.therefore ,the recoil velocity of the rifle is 0.038 m/s .