Question

A bullet of mass 200 g. If kinetic energy is 100 J, then it's speed will be?

Answer 1

Step-by-step explanation:

ke=1/2mv²

100=1/2200v²

1=v OK friend this is urs answer

Answer 2

Answer:

v=32ms^-1

Step-by-step explanation:

Given mass of the bullet is 200g=0.2kg

kinetic energy (KE)=100J

We know that,

KE=1/2mv^2

=>2KE=mv^2

=>v^2=2KE/m

=>v^2=2×100/0.2

=>v^2=1000

=>v=√1000

=>v=31.62277660168 ms^-1

=>v=32ms^-1