Question

A bullet of mass 200 g.if kinetic energy is 100 J,then it,s speed will be?

Answer 1

Answer:

200÷ 100= 2m/ sec is the speed of bullet hope it helps you have a great day

Answer 2

Answer:Mass of bullet, m=100g=  100/1000kg=1/10kg

Velocity of bullet, v=100ms  −1

 Mass of gun, M=20kg

Let recoil velocity of gun =V

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

=mv+MV=  1/10×100+20V=10+20V

Applying law of conservation of momentum, Final momentum = Initial momentum

i.e., 10+20V=0

20V=−10

or V= -10/20=−0.5ms  −1 .

Negative sign shows that the direction of recoil velocity of the gun is opposite to the direction of the velocity of the bullet.

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