Question

A bullet of mass 200 g is moving with a velocity 4 m/s. Its kinetic energy is
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Answer 1

Given :

Mass of the bullet (m) = 200 g = 0.2 kg

Velocity of the bullet (v) = 4 m/s

To find :

Kinetic energy of the bullet

Solution :

Kinetic energy is directly proportional to the mass of the object and to the square of its velocity. It is scalar quantity

${ \leadsto{ \bf{K.E = \dfrac{1}{2} m {v}^{2} }}}$

${ \leadsto{ \sf{ K.E = \dfrac{1}{2} (0.2) {(4)}^{2} }}}$

${ \leadsto{ \sf{ K.E = (0.2) (8)}}}$

${ \leadsto{ \boxed{ \bf{K.E = 1.6 J }}}}$

thus, Kinetic energy of the bullet is 1.6 J

Remember !

SI unit of kinetic energy is joules.

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