a bullet of mass 200g fired from a gun moving with a velocity of 20m/s hits a wooden block. The bullet stops after traveling a distance of 40cm in the wooden block. calculate the retarding force exerted by the block on the bullet
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Answer:
Given,
Mass of Bullet (m) = 200 g
= 0.2 kg
Initial Velocity (u) = 20 m/s
Final Velocity (v) = 0 m/s
Distance travelled by penetration (S) = 40 cm
= 0.4 m
v² = u²-2aS
= 0 = (20)² - (2*a*0.4)
= 0 = 400 - 0.8a
= 0.8a = 400
= a = 500 m/s²
The Retardation caused is 500 m/s²,
Retarding/Resistive Force = ma
= 0.2*500
= 100 N
I hope this helps.
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