a bullet of mass 20g and moving with 600m/s collides with a block of mass 4kg hanging with string. What is velocity of bullet when it comes out of block if block rises to height 0.2m after collision???
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Answered by
26
Prefer the attachment above⤴️⤴️⤴️
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Answered by
20
Here i considered the system to be in vertical osscilatory motion.
**Shyd step 1 samajh aa jaaye yaa agr naa aaye to attachement 2 dekhna**
In the attachment at point P velocity of block becomes zero i.e.
considering it to be an oscillatory motion ¼ evolution has been completed till point P .
Now conserving energy at point P and A.
refer to the attachement
finally the velocity of the block which we get at position a is under root 2gh which is independent of length of the pendulum or the system .
this is what I used in the first step in solving this question .
Hope you will get it.
khushi here✔️✌
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