Question

a bullet of mass 20g and with the velocity of 150ms-1 moving horizontally strikes a wooden material and comes to rest in 0.02 s.calculate the magnitude of the force exerted by the wooden material on the bullet

Answer 1

am solving hope it helps u........15N is answer

Answer 2

Answer:

Given:

• A bullet of mass 20g and with the velocity of 150m/s moving horizontally strikes a wooden material and comes in rest in 0.002 seconds.

Find:

• Calculate the magnitude of the force exerted by the wooden material on the bullet.

Know terms:

1. Mass = (m)
2. Force = (F)
3. Initial velocity = (u)
4. Final velocity = (v)
5. Time = (t)
6. Newton = (N)

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{F = \dfrac{m * v-u}{t} }}}}}}$

Calculations:

⇒ $\bold{F = \dfrac{0.02 * 0-150}{0.002}}$

⇒ $\bold{F = \dfrac{0.02 * 150}{0.002}}$

⇒ $\bold{F = \dfrac{3}{0.002}}$

⇒ ${\sf{\underline{\boxed{\red{\sf{F = 1500 \: N }}}}}}$