Question

a bullet of mass 20g is fired from a pistol of mass 2kg with horizontal velocity of mass of 150m/s calculate the recoil velocity of pistol

Answer 1

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հίί ʍαtε_______✯◡✯
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һєяє' ʏȏȗя ѧṅśwєя ʟȏȏҡıṅɢ ғȏя________
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✯given that,

▶m1= 0.02kg(20g)

♦u1=0m/s

♦v1 = 150m/s

▶m2 = 2kg

♦u2= 0m/s

♦v2= v.

▶ using law of conservation of momentum,

♦m1u1 + m2u2 = m1v1 + m2v2

♦0.02*0 +2* 0 =0.02*150 + 2* v
⇒0 +0 =3 + 2v
⇒3 = 2v
⇒3 / 2 = v
⇒1.5 = v

hence,

⭐recoil velocity = 1.5 m/s

$hope \: it \: helps$


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Answer 2

▶m1= 0.02kg(20g)

♦u1=0m/s

♦v1 = 150m/s

▶m2 = 2kg

♦u2= 0m/s

♦v2= v.

▶ using law of conservation of momentum,

♦m1u1 + m2u2 = m1v1 + m2v2

♦0.02*0 +2* 0 =0.02*150 + 2* v

⇒0 +0 =3 + 2v

⇒3 = 2v

⇒3 / 2 = v

⇒1.5 = v