Question

A bullet of mass 20g is fired from a rifle of 8 kg with an initial velocity of 100m/s find the final velocity of the recoil of the rifle

Answer 1

Answer:

The velocity of recoil of the rifle=-0.25m/s

Explanation:see the picture for explanation

Answer 2

Answer:

0.25 m/s

Explanation:

The question is some type of LAW OF CONSERVATION OF MOMENTUM .

mass of gun (m1) = 8 kg

mass of bullet (m2) = 20 g = 0.02 kg

Initial velocity of gun(u1) = 0 m/s

Initial velocity of bullet (u2) = 0 m/s

Final velocity of gun (v1) = v1

Final velocity of bullet (v2) = 100 m/s

We have the formula,

m1.u1 + m2.u2 = m1.v1 + m2.v2

substituting values

(8)(0) + (0.02)(0) = (8)(v1) + (0.02)(100)

0 = 8v1 + 2

-2 = 8v1

v1 = -2/8

v1 = -1/4 = -0.25 m/s recoil

Therefore the gun will experience a recoil of 0.25 m/s ...

The sign is negative because direction of gun is opposite to that of the bullet

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