A bullet of mass 20g is fired from a rifle with a velocity of 800 m/s after passing through a mud wall100cm
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Explanation:
Given A bullet of mass 20 g is fired from a rifle with a velocity of 800 m/s after passing through a mud wall 100 cm t he velocity drops to 100 m / s. What is the average resistance of the wall neglecting friction due to air?
We know that mass m = 20 g, initial velocity u = 800 m/s, final velocity v = 100 m/s
Mass m = 0.02 kg
Now there is a loss in kinetic energy.
Therefore loss in kinetic energy will be
½ mu^2 – ½ mv^2
½ m(u^2 – v^2)
½ x 0.02 (800^2 – 100^2)
= ½ x 0.02 x (800 + 100)(800 – 100)
= ½ x 0.02 x 900 x 700
= 6300 J
Now according to work-energy formula we know that
W = F x S ( S = 100 cm = 1 m)
6300 = F x 1
So F = 6300 N
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