A bullet of mass 20g is fired horizontally with the velocity of 150 m/s from pistol of mass 2 kg find the recoiling velocity of pistol
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By using law of conservation of momentum recoil velocity is given as
v = mu / M
= (20 × 10^-3) × 150 / (2)
= 1.5 m/s
Recoil velocity of gun is 1.5 m/s
v = mu / M
= (20 × 10^-3) × 150 / (2)
= 1.5 m/s
Recoil velocity of gun is 1.5 m/s
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