a bullet of mass 20g is fired horizontally with velocity 100 m/s from pistol of mass 1.5 kg calculate the recoil velocity of pistol
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Answered by
9
According to law of conservation of momentum,
m1u1+m2u2=m1v1+m2v2
u1,u2=initial velocities of bullet and gun
v1,v2=final velocities of bullet and gun
m1v1= -m2v2
(20/1000)×100= -1.5×v2
v2= -2/1.5
v2= -4/3 m/s
Negative sign shows that recoil velocity is opposite to firing velocity.
m1u1+m2u2=m1v1+m2v2
u1,u2=initial velocities of bullet and gun
v1,v2=final velocities of bullet and gun
m1v1= -m2v2
(20/1000)×100= -1.5×v2
v2= -2/1.5
v2= -4/3 m/s
Negative sign shows that recoil velocity is opposite to firing velocity.
Anonymous:
bro u r wrong
then tell me the correct
I don't know but the procedure here is different
what is the ans??
then why did u asked??
if I had knew I would not question
which procedure are u talking about??
I know the procedure but don't know to soly
ok report the question, if it is wrong then it will be automatically deleted
Answered by
11
Heya user !!
Here's the answer you are looking for
Please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Here's the answer you are looking for
Please see the attached file for your answer
★★ HOPE THAT HELPS ☺️ ★★
Attachments:
what?
where?
in answer
which part of the answer
from start 4th line
That means what ever I have written above it is also there.... " → this indicates ditto...
ok
u2 is the initial velocity of the gun.... hope you got now!!!
thanks I copied it in homework
:-)
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