Question

A bullet of mass 20g is fired with a velocity of 300 m/s and
Hits stationary wooden board.
Come to rest in 0.03sec.find depth of penetration of the bullet into the block

Answer 1

Answer:

mass=20g =20÷1000kg

initial velocity = 300m/s

final velocity =0m/s

time =0.03s

acceleration =v-u÷t

0- 300÷ 0.03

-300 ÷0.03

-300 × 100÷3

-10000m/s square

F=ma

F= 20÷1000× -10000

F= 20×-10000÷1000

F= -200 N

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