A bullet of mass 20g is horizontally fired with velocity 150m/s from a pistol of mass 2kg. what is the recoil velocity of the pistol
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Answer:For this question we will use consevasion of momentum -
m1v1 +m2v2 = m1u1 + m2u2
m1 = 20g = 0.020 kg = 20/1000 kg
u1 = 0m/s
v1 = 150m/s
m2 = 2 kg
u2 = 0m/s
v2 = unknown = v
= [ 20/1000 * 150 ] + [ 2v ] = [ 20/1000*0] + [ 2 * 0 ]
= 3 + 2v = 0
= 2v = -3
= v = -3/2
= v = -1.5m/s
ANS---- The Recoil velocity of the pistol is -1.5m/s
Explanation:
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