Question

A bullet of mass 20g is moving with a velocity of 600 m/s. Find the Kinetic Energy of the bullet​

Answer 1

Explanation:

Before collision,

Momentum of bullet =

1000

20

×600=12kgm/s

Let V

2

,V

3

be velocities of bullet and block after the collision.

Using conservation of momentum,

⇒12=

1000

20

×V

2

+4V

3

Given height reached by the block =0.2m

Using conservation of energy for the block:

Change in K.E = Work done

⇒

2

1

×4×V

3

2

=4×10×0.2

⇒V

3

=2m/s

On solving for V

2

:

V

2

=

(

1000

20

)

12−8

=200m/s

Answer 2

Answer:

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