Question

A bullet of mass 20g moving with a speed of 75 m&s hits a fixed wooden plank and comes to rest after penetrating a distance of 5 cm what is the average resistive force exerted by the wooden plank on the bullet

Answer 1

M=20g=.02kg
V=0m/s
S=5cm=.05m
V=0m/s
Since,
V²=u²+2as
Putting value
0=75²+2(.05)a
0=5625+.1a
-5625=.1a
-56250m/s²=a
Now,
F=ma
F=.02×-56250
F=-1125kg/m²=-1125N
(ÆÑẞWĒR)

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