a bullet of mass 20g moving with a speed of 75m/s hits a fixed wooden plank and comes to rest after penetrating a distance of 5 cm.wht is the average resistive force exerted by wooden plank on bullet
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Answered by
20
To solve the average
force exerted by the wooden plank on bullet use the given formula :-
We don't know the average force by the bullet , so let it be m/s²
⇒ Final velocity of bullet = v = 0
⇒Initial velocity of the bullet = u = 75 m/s
⇒ Distance = s = 5cm =
⇒ Now , let us substitute the values in the formula :-
→ Therefore , we get acceleration as -56250 m/s²
⇒ Now , let us find the force :-
f = 0.02 kg × ( - 56250 )
f = -1125 Newton
Hence the average force is N
We don't know the average force by the bullet , so let it be m/s²
⇒ Final velocity of bullet = v = 0
⇒Initial velocity of the bullet = u = 75 m/s
⇒ Distance = s = 5cm =
⇒ Now , let us substitute the values in the formula :-
→ Therefore , we get acceleration as -56250 m/s²
⇒ Now , let us find the force :-
f = 0.02 kg × ( - 56250 )
f = -1125 Newton
Hence the average force is N
Answered by
11
m=20 g=20/1000=.02 kg
v=0 m/s,since the bullet comes to rest
u=75 m/s
s=5 cm=5/100 m=.05 m
a=?
To find we can use v^2-u^=2as
0-75^2=2*a*.05
-5625=.1a
a=-5625/.1=-56250
to find the resistive force use this formulae
f=ma
f=0.02*-56250=-1125N
therefore the average resistive force is -1125 Newton
v=0 m/s,since the bullet comes to rest
u=75 m/s
s=5 cm=5/100 m=.05 m
a=?
To find we can use v^2-u^=2as
0-75^2=2*a*.05
-5625=.1a
a=-5625/.1=-56250
to find the resistive force use this formulae
f=ma
f=0.02*-56250=-1125N
therefore the average resistive force is -1125 Newton
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