Question

A bullet of mass 20g moving with a velocity of 200mpers gets embeded in a wooden block of mass 980g calculate the velocity acquired by a block

Answer 1

Mass = 20 g OR 1/50 kg
Velocity = 200 m/sec

Momentum of Bullet = Mass × Velocity

=> 1/50 × 200

=> 4 kg m/sec

Let the velocity acquired by block be x

Mass = 980g OR 49 / 50 kg

Momentum of Block after bullet gets embedded = Mass × Velocity 

=> 49 x / 50 kg m/sec

APPLYING LAW OF CONSERVATION OF MOMENTUM,

Momentum of bullet = Momentum of block after bullet gets embedded

=> 4 = 49 / 50 x

=> x = 200 / 49

=> x = 4.08

Answer: 4.08 m/sec

Answer 2

Given:

Mass of bullet = 20 g

= 20/1000

= 1/50 kg

Velocity = 200 m/sec

then,

Momentum of bullet = Mass × Velocity

1/50 × 200 = 4 kg m/sec.

now,let x be the velocity acquired by the block

Mass of Block = 980 g

= 980/1000 kg

= 49/50 kg

Momentum of Block = Mass × Velocity

4 = 49/50 × X = 49/50 X

X = 200/49

= 4.08.....................

∴ the ans is 4.08.............

hope this helps u

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