A bullet of mass 20g travelling with a velocity of 100m/s strikes a mud wali-40cm thick and comes out with a velocity of 50m s. Find the opposing force exerted by the wall.
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Answer:
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Answer:
Mass of bullet (m)= 20 g = 0.02 kg
Initial velocity of bullet (u) =100 m/s
Final velocity of bullet (V) = 0
Time (t)= 0.05 seconds
Acceleration on the bullet (a)?
Force acting on wooden block (F) = ?
Distance penetrated by bullet (s) = ?
We know;
Step 1: Calculate the acceleration of the v = u + at
0= 100+ a ×0.05
– a × 0.05 = 100
a = -2000 ms-2
Step 2: Calculate the distance of penetration using s = ut + ½ at2
= 100 × 0.05 + 0.5 x (–2000) × (0.05)2
= 7.5 m
We know, F = ma
Force acting on bullet (F)
= 0.02 × (– 2000) = -40N
Negative sign denotes that wooden block exerts force in the direction, opposite to the direction of motion of the bullet.
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