Question

A bullet of mass 20gm is fired from a riffle of mass 8kg with a velocity of 100 m/s. THe velocity of recoil ofthe rifle is ​

Answer 1

Answer:

mass of bullet m1= 20gm = 20÷1000

kg=0.020kg

velocity of bullet v 1 =100 m/s

mass of rifle m2 =8 kg

Let velocity of recoil of rifle be v2

Using the law of momentum conservation,

m1 u1 +m2u2 = m1v1 m2v2

Since, initially the bullet and rifle are at rest.

Hence, u1 =0, u2 =0

On substituting the values, we get

0.020×100=8×−v

v=−0.25m/s

Here. negative sign shows that the direction is opposite to motion of bullet.

Explanation:

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