Question

A bullet of mass 20gm moving with a velocity of 400 m/s gets embedded in a freely suspended wooden block of mass 900gm. What is the velocity acquired by the block?

Answer 1

Mass 1 = 0•02 kg m 2 = 0•9
U 1 = 400 m / s u2 = 0
M1u1 +M2u2 = (m1+m2) v
0•02 ×400 + 0•9 +0 = (0•02+0•9)v
8 = (0•92)v
v = 8 / 0•92