Question

A bullet of mass 20kg is horizontally fired with a velocity of 150m/s for a pistol of mass 2kg what is the recoil velocity of the pistol ​

Answer 1

Answer:

Here is your answer!!

Explanation:

Mass of bullet, m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (u1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

The total momentum of the pistol and bullet is zero before the fire. (Since both are at rest)

The Total momentum of the pistol and bullet after it is fired is

= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

 3 + 2v = 0

→v = -1.5 m/s  

Thus, the recoil velocity of the pistol is 1.5 m/s.

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