Question

A bullet of mass 25 g and velocity 50 ms? passes through a board 7.5 cm thick and emerges und of 1-40 ms-1. What is the average force exerted by the board on the bullet? v=ur zal (17150 N (2) 15 N - (3) 1.5 N 2 (4) 0.15 N foma​

Answer 1

Answer:

A bullet of mass 25g and velocity 50m/s passes through board 7.5 cm thick and emerges with a velocity of 40m/s. What is the average force exerted by board on the bullet?

The Work-Energy theorem states that,

ΣW=ΔK.E (Work done equals change in kinetic energy)

F x S = 1/2 m v^2 - 1/2 m u^2

F = 1/2mv^2 - 1/2mu^2 / s

F = 1/2 x 1/40 (50^2–40^2) / 0.075

F = 11.25/0.075 = 150N (Ans)

Answer 2

Answer:

Work = Fd

Work = ∆0.5 mv^2

Fd = ∆0.5mv^2

Fd = 0.5 x 0.025 x 50^2 - 0.5 x 0.025 x 40^2

Fd = 11.25

F = 11.25/0.075

F = 150 N

Explanation:

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