Question

A bullet of mass 25 g is fired from a gun with a velocity

of 400 ms–1. After passing through a target 20 cm

thick its velocity drops to 100 ms–1

Calculate the

resistance offered by the target
Please answer only if you know fast ​

Answer 1

Answer:

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Explanation:

conserving the momentum of system.

0.025∗400+4.975∗0.0=(4.975+0.025)∗v

v=10/5=2m/s

Answer 2

Answer:

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