Physics, asked by krithiksendhilkumar, 5 months ago

A bullet of mass 25 g is fired from a gun with a velocity of 400 ms–1. After passing through a target 20 cm thick its velocity drops to 100 ms–1.

Answers

Answered by krithiksendhuren
0

Answer:

Can i say the ansswerr

Explanation:

Answered by sunitatyagi848
0

Explanation:

conserving the momentum of system.

0.025∗400+4.975∗0.0=(4.975+0.025)∗v

v=10/5=2m/s

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