Question

A bullet of mass 25 g is horizontally fired with a velocity 200 m/s from a pistol of mass 2.5 kg. What is the recoil velocity of pistol?​

Answer 1

Answer:

5000m/s

Explanation:

Intial velocity of pistol = 0m/s

Final velocity = x m/s

Initial velocity of bullet = 200m/s

Final velocity = 0m/s

By law of conservation of momentum,

25 ×200 + 2.5 × 0 = 25 × 0 + 2.5x

5000 = 2.5x

x = 5000/2.5

x = 50000/25 = 2000m/s