Question

a bullet of mass 25 g moving with a velocity of 200 cm/s is stopped within 5 cm of the target. the average resistance offered by the target is​

Answer 1

Answer:

The average resistance force is 10000 N.  

Explanation:

Step 1: The shift in momentum divided by the amount of time needed to stop the bullet yields the average resistance force. Half of a* t2 is the distance travelled when the force is constant. The velocity difference divided by the time represents the average acceleration.

Using a multimeter or digital volt metre to measure the resistance of your own skin is a helpful practise (DVM). Take hold of the leads and set the metre to measure resistance in the 100 K ohm region. Keep track of your strength. Then, apply more pressure to the wires while maintaining as much contact area as you can, and again note the resistance.

Step 2:  A bullet of mass 25g moving with a speed 200 m/s is stopped within 5 cm of the target.

The mass of the bullet is 25 g.

The initial velocity of the bullet is u=200 m/s.

The final velocity is v=0 m/s.

The distance covered is 5 cm.

Into m, 5 cm=0.05 m.

First we find the acceleration.

Using formula,

$2 a s=v^2-u^2$

Substitute the values,

$\begin{aligned}& 2 a(0.05)=0^2-200^2 \\& 0.1 a=-40000 \\& a=-\frac{40000}{0.1} \\& a=-400000 \mathrm{~m} / \mathrm{s}^2\end{aligned}$

Converting mass into kg,

25 g= 0.025 kg.

Now, The average resistance force offered by the target is

$\begin{aligned}& F=m \times a \\& F=0.025 \times 400000 \\& F=10000\end{aligned}$

The average resistance force is 10000 N.

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