Question

A bullet of mass 25 g strikes a target with a velocity of 400 m/s. Calculate:
(a) its K.E. when it strikes the target
(b) the work done by the bullet on the target (c) the opposing force of the target if the bullet penetrates to a depth of 20 cm​

Answer 1

Answer:

In the first case the initial velocity(u) = 80 m/s and distance travelled(s) = 50 cm.

But, here the final velocity =0, thus

0=u2−2as     ( negative sign because some resistive force is acting )

a=6400m/s2

In the second case case acceleration (a)=6400m/s2

Substituting in equation, we have

v12=u12−2as1

=(80)2−2×6400×41

=6400−3200

=3200 or v1=402

The emerging velocity is 402m/s.

Explanation:

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