Question

a bullet of mass 25 gm is horizontally fired from a pistol of mass 2.5 kg. what is the recoil velocity of the pistol? ​

Answer 1

Answer:

$-\frac{u}{100}$

Explanation:

Given :

m₁ = 25 gm

v₁ = u

m₂ = 2.5 kg

v₂ = v

Procedure :

As per the law of conservation of momentum,

m₁v₁ = m₂v₂

[Also, 25 gm = 25/1000 kg ]

⇒ $\frac{25}{1000} u = 2.5 v$

⇒ v = -(0.01)u

Thanks !

Answer 2

Answer:

This is your answer.

Hope it will help you..