Question

A bullet of mass 25 gram is horizontally fired with a velocity 200 m s -1 pistol of mass 2.5 kg ?What is the recoil velocity of pistol?
please explain step by step.

Answer 1

Explanation:

The target distance is 45.7m and the bullet speed is 460m/s

The time taken by the bullet to reach the target is 45.7/460 = 0.099s

During flight the bullet will go downwards by some height. Taking g = 9.8m/s² this will be

h = ut + gt²/2, here u = 0

So h= 9.8*(0.99)²/2 = 0.048m = 4.8 cm

So the rifle should be pointed 4.8cm higher from the center of the target keeping it horizontal.

I think this will work.