Question

a bullet of mass 25 grams is fired from a gun of mass 3.5 kg with a speed of 200 m/s calculate the recoil velocity of the gun​

Answer 1

Answer:

Mass of bullet, m=100g=  

1000

100

​

kg=  

10

1

​

kg

Velocity of bullet, v=100ms  

−1

 

Mass of gun, M=20kg

Let recoil velocity of gun =V

Before firing, the system (gun+bullet) is at rest, therefore, initial momentum of the system =0

Final momentum of the system = momentum of bullet + momentum of gun

=mv+MV=  

10

1

​

×100+20V=10+20V

Applying law of conservation of momentum, Final momentum = Initial momentum

i.e., 10+20V=0

20V=−10

or V=−  

20

10

​

=−0.5m/s  

Answer 2

Answer:

1.42857 m/s

hope it helps you