Physics, asked by shankar9653, 10 months ago

A bullet of mass 25 grams with a speed of 60 metre per second enters a heavyheavy wooden block and Stop by the distance of 100m what is the average resistive force exerted by the block and the bullet ​

Answers

Answered by Anonymous
4

Answer:

here's a solved answer

hope it will help u

Explanation:

Màrk às bràíñlìest rîght ñõw plèásē.

Attachments:
Answered by mourfiousamanraj
0

Answer:

o.45 Newton

Explanation:

u= 60

s= 100

so...

you know that...

2as = (v)^2 - (u)^2

2as = 0 - 3600

a= -3600/200

a = -18

f = ma = (25/1000)18 = 0.45 newton

where

a - acceleration

plzzz.. mark it as brilient answer

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