A bullet of mass 25 grams with a speed of 60 metre per second enters a heavyheavy wooden block and Stop by the distance of 100m what is the average resistive force exerted by the block and the bullet
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Answer:
here's a solved answer
hope it will help u
Explanation:
Màrk às bràíñlìest rîght ñõw plèásē.
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Answer:
o.45 Newton
Explanation:
u= 60
s= 100
so...
you know that...
2as = (v)^2 - (u)^2
2as = 0 - 3600
a= -3600/200
a = -18
f = ma = (25/1000)18 = 0.45 newton
where
a - acceleration
plzzz.. mark it as brilient answer
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