Question

A bullet of mass 25g moving with a speed 200 m/s is stopped within 5 cm of the target .what is average resistance force offered by the target?

Answer 1

Hope this helps you.

Answer 2

Answer:

The average resistance force is 10000 N.            

Step-by-step explanation:

Given : A bullet of mass 25g moving with a speed 200 m/s is stopped within 5 cm of the target.

To find : What is average resistance force offered by the target?

Solution :

The mass of the bullet is 25 g.

The initial velocity of the bullet is u=200 m/s.

The final velocity is v=0 m/s.

The distance covered is 5 cm.

Into m, 5 cm=0.05 m.

First we find the acceleration.

Using formula,

$2as=v^2-u^2$

Substitute the values,

$2a(0.05)=0^2-200^2$

$0.1a=-40000$

$a=-\frac{40000}{0.1}$

$a=-400000m/s^2$

Converting mass into kg,

25 g= 0.025 kg.

Now, The average resistance force offered by the target is

$F=m\times a$

$F=0.025\times 400000$

$F=10000$

Therefore, The average resistance force is 10000 N.