a bullet of mass 2g is having a charge 4uc the potential difference through which it should move to acquire a speed of 10m/s starting from rest
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ma = mg a = g = 1 × 10 = 10m/s2 For crossing the bridge in minimum time, it has to travel with maximum acceleration u = 0, s = 500m, a = 10m/s2 s = ut + ½ at2 500 = 0 + (1/2) 10 t2
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Explanation:
Answer:
ma = mg a = g = 1 × 10 = 10m/s2 For crossing the bridge in minimum time, it has to travel with maximum acceleration u = 0, s = 500m, a = 10m/s2 s = ut + ½ at2 500 = 0 + (1/2) 10 t2
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