a bullet of mass 30 g is fired from a gun and acquires a velocity of 400 m/s get embedded into a wooden block of mass 470 g Calculate velocity through which wooden block moves
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Answer:
Bullet :-
Mass = 30 g => 0.03 kg
Velocity = 400 m/s
Wooden Block :-
Mass = 470 g + 0.03 kg (bullet is embedded )
Mass = 0.47 kg + 0.03 kg
Velocity = v
We know that :-
Momentum of Bullet = recoil momentum of gun
0.03 × 400 = 0.5 × v
12 = 0.5 v
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