Question

A bullet of mass 30 g is fired from a gun with a muzzle velocity 50 ms --2. Find the recoil of the gun if
its mass is 3 kg.
What is the law of inertia?​

Answer 1

Answer:

Mass of the gun m

1

=3kg

Mass of the bullet m

2

=30 g=0.03 kg

Velocity of bullet v

2

=100 m/s

i) According to the law of conservation momentum

m

1

×v

1

=m

2

×v

2

3×v

1

=0.03×100

Recoil velocity v

1

=

3

100×0.03

=1m/s

ii) Initial velocity of the gun u=0 m/s

Final velocity of the gun v=1m/s

Time t=0.003 s

Acceleration a=

t

v−u

=

0.003

1−0

=

3

1000

m/s

2

Force=m×a=3×

3

1000

=1000N

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