Question

) A bullet of mass 30 g is horizontally fired with a velocity 100m/s from a pistol of mass 1.5 kg .What is the recoil velocity of the pistol ? ​

Answer 1

Answer:

Mass of bullet =30g

30/1000=0.03kg

Velocity of the bullet= 100m/s

Mass of the pistol = 1.5kg

MV -mv=0

V= mv/M

=(0.03×100)/1.5

=2m/s

Answer 2

A bullet of mass 30 g is horizontally fired with a velocity 100m/s from a pistol of mass 1.5 kg .

What is the recoil velocity of the pistol ? ​

Given:-

Mass of the bullet(m)=30g

=>30/1000

=>0.03kg

Velocity of the bullet(v)=100m/s

Mass of the pistol(M)=1.5kg

To find:-

Recoil velocity of the gun(V)

Solution:-

By law of conservation of momentum, we get-----

=>MV-mv=0

=>V=mv/M

=>(0.03×100)/1.5

=>2m/s

Thus, recoil velocity of the gun is 2m/s.