Question

A bullet of mass 30 G moving with an initial velocity 0.1 km per second strikes woolen block and comes to rest after penetrating a distance of 5 cm calculate the retardation caused by the wooden block and the force exerted by the block​

Answer 1

Answer:

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Explanation:

Mass of the bullet is mb=50gm=0.05Kg

Initial velocity of bullet ub=100m/s

Final velocity is vb=0m/s

(1) Initial momentum of bullet pi=mbub=5Kgm/s

(2) Final momentum of bullet pf=mbvb=0.05×0=0

(3)  Retardation occurred by the wooden block is

v2−u2=2as

−(100)2=2a(0.02)

a=−250000m/s2

(4) Resistive force

F=ma

=0.05×−250000

=12500N