Question

A bullet of mass 30 gm is horizantally fired with a velocity 250 m/second sq. from a pistol of mass 3 kg. What is the recoil velocity?​

Answer 1

Answer:Down

Explanation:

Mass of bullet, m1 = 20g (= 0.02 kg)

Mass of pistol, m2 = 2 kg

Initial velocity of the bullet (u1) and pistol (u2) = 0

Final velocity of the bullet, v1 = +150m s-1

Let v be the recoil velocity of the pistol.

The total momentum of the pistol and bullet is zero before the fire. (Since both are at rest)

Total momentum of the pistol and bullet after it is fired is

= (0.02 kg x 150 m s-1) + (2 kg x v m s-1)

= (3 + 2v) kg m s-1

Total momentum after the fire = Total momentum before the fire

3 + 2v = 0

→v = -1.5 m/s  

Thus, the recoil velocity of the pistol is 1.5 m/s.