a bullet of mass 30g is fired horizontally with a velocity of 120 m/s from a pistol of mass 2 kg , the rocoil velocity of the pistol is
Answers
Recoil velocity of pistol = 2.25 m/s
Explanation:
given that,
a bullet of mass 30 g is horizontally fired with a velocity of 150 m/s is fired by a pistol
so,
here,
mass of bullet = 30 g
by converting of 30 g into kg
= 30 /1000
= 0.03 kg
velocity of bullet = 150 m/s
so here,
momentum of bullet will be
mass of bullet × velocity at which it fired
putting the values,
Momentum = 0.03 kg × 150 m/s
= 4.5 kgm/s
now,
also given that
the mass of pistol = 2 kg
let the velocity at which the pistol recolled be v
now,
momentum of pistol
= mass of pistol × recoil velocity of pistol
putting the values
2 × v
= 2v
now,
by the law of conservation of momentum
➡The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
so,
ACCORDING TO THE LAW OF CONSERVATION OF MOMENTUM
2v = 4.5
v = 4.5/2
v = 2.25 m/s
so,
Recoil velocity of pistol = 2.25 m/s
Answer:Recoil velocity of pistol = 2.25 m/s
Explanation:
given that,
a bullet of mass 30 g is horizontally fired with a velocity of 150 m/s is fired by a pistol
so,
here,
mass of bullet = 30 g
by converting of 30 g into kg
= 30 /1000
= 0.03 kg
velocity of bullet = 150 m/s
so here,
momentum of bullet will be
mass of bullet × velocity at which it fired
putting the values,
Momentum = 0.03 kg × 150 m/s
= 4.5 kgm/s
now,
also given that
the mass of pistol = 2 kg
let the velocity at which the pistol recolled be v
now,
momentum of pistol
= mass of pistol × recoil velocity of pistol
putting the values
2 × v
= 2v
now,
by the law of conservation of momentum
➡The total momentum of the two objects before the collision is equal to the total momentum of the two objects after the collision.
so,
ACCORDING TO THE LAW OF CONSERVATION OF MOMENTUM
2v = 4.5
v = 4.5/2
v = 2.25 m/s
so,
Recoil velocity of pistol = 2.25 m/s