Question

A bullet of mass 30g is fired horizontaly with a velocity of 120 m/sec from a pistol of mass 2 Kg. Determine the

recoil velocity of the pistol.​

Answer 1

Answer:

• -1.8 m/s  
• Let recoil velocity of gun be V
• Mass of bullet(m) = 30 g
• Velocity of bullet(v) = 120m/s
• Momentum of bullet = m*v = 30*120 gm/s = 3600 m/s
• Mass of gun(M) = 2 kg = 2000 g
• According to law of conservation of momentum,
• m*v = -M*V
• =>V = (m*v)/-M
• =>V = -3600/2000
• =>V = -1.8 m/s