Physics, asked by naazjyoti6023, 10 months ago

A bullet of mass 40 g moving with a speed of 90 m/s enters a heavy wooden block and is stopped after a distance of 60 m The average hasty force exerted by the block on the bullet is

Answers

Answered by surya2634

0

Answer:

90*60 = 5400

5400/40 = 135

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